Achemist measures the amount of bromine liquid produced during an experiment. she finds that 14.4 g of bromine liquid is produced. calculate the number of moles of bromine liquid produced.
round your answer to 3 significant digit

The number of mole of bromine liquid produced is 0.09 mole  

The mole of an element as it relates to its mass and molar mass, can be obtained by using the following equation:

With the above formula, we can obtain the number of mole bromine liquid produced. This can be obtained as follow:

Mass of bromine liquid (Br₂) = 14.4 g

Molar mass of bromine liquid (Br₂) = 2 × 80 = 160 g/mol

Mole = mass / molar mass

Mole of bromine liquid = 14.4 / 160

Therefore, the number of mole of bromine liquid produced is 0.09 mole

Learn more: link

Explanation:

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o