The partial pressure of carbon dioxide in the atmosphere is 0.239 torr. calculate the partial pressure in mm hg and cant round each of your answers to 3 alg x 5 ?

Explanation:

It is known that 1 torr equals 1 mm Hg.

Therefore, 0.239 torr will be converted into mm Hg as follows.

                     1 torr = 1 mm Hg

So,          0.239 torr =

                                 = 0.239 mm Hg

It means that 0.239 torr is equal to 0.239 mm Hg.

Therefore, we can conclude that partial pressure of given carbon dioxide in mm Hg is 0.239 mm Hg.

its first and third is your answer i did the qustion the fourth isnt right

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.