Consider a balloon with volume v. it contains n moles of gas and has an internal pressure of p. the temperature of the gas is t. the balloon is placed in a freezer at temperature 0.75t. the freezer is pressurized at 1.25p. which of these could be the final volume of the balloon?

V₂ = 0.6 V.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

(P₁V₁T₂) = (P₂V₂T₁).

V₁ = V, P₁ = P, T₁ = T.

V₂ = ??? V, P₂ = 1.25 P, T₂ = 0.75 T.

∴ V₂ = (P₁V₁T₂)/(P₂T₁) = (P)(V)(0.75 T)/(1.25 P)(T) = 0.6 V.

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.