The ka of acetic acid is 1.76 × 10-5. the ph of a buffer prepared by combining 50.0 ml of 1.00 m potassium acetate and 50.0 ml of 1.00 m acetic acid is

pH = 4.75

Explanation:

Given:

Ka(acetic acid, CH3COOH) = 1.76*10^-5

Volume of CH3COOK = 50.0 ml

Molarity of CH3COOK = 1.00 M

Volume of CH3COOH = 50.0 ml

Molarity of CH3COOH = 1.00 M

To determine:

pH of the above buffer solution

Calculation:

The pH of a buffer is related to the concentrations of the conjugate base and acid via Henderson - Hasselbalch equation:

where pKa = -logKa

{A-] = conjugate base

[HA] = acid

For the CH3COOH/CH3COOK buffer:

here, [CH3COOK] = [CH3COOH], therefore,

zfoods? ok, pressure is used to keep the heat inside and to keep the food perfect.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j