7) find ah° for the reaction c3hg(8) + 5 o2(8) - 3 co2(8) + 4 h2o(l). ah° = -2046 kj for the reaction: c3h8(8) + 5 o2(8) - 3 co2(g) + 4h2o(8) the heat of vaporization of water is 44.0 kj/mol. the standard enthalpy of formation of water and water vapor are -285.9kj/mol and -241.8 kj/mol, respectively. note that h20 is a liquid in the first reaction and a gas in the second. 0-1870 kj 0- kj o-2002 kj 0-2090 kj

nacl is added to the aqueous of what? ? in order to get a proper answer you have to specify the exact composition of the aqueous solution.

so what is the problem with your lab report and whats the subject of the lab report? i will you

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole