Complete and balance the equation for the following acid-base neutralization reaction. if water is used as a solvent, write the reactants and products as aqueous ions. in some cases, there may be more than one correct answer, depending on the amount of reactants used.
(a)mg(oh)2 + hclo4?
(b)so3 + h2o? (assume an excess of water and that the product dissolves)
(c) sro + h2so4?

Explanation:

A balanced equation is defined as the one that has equal number of atoms of all the elements present on both reactant and product side.

(a)

Number of atoms on reactant side are as follows.

Mg = 1

O = 6

H = 3

Cl = 1

Number of atoms on product side are as follows.

Mg = 1

O = 9

H = 2

Cl = 2

So, to balance this equation we multiply by 2 on reactant side and multiply by 2 on product side.

Therefore, the balanced reaction equation is as follows.

(b)  

Number of atoms on reactant side are as follows.

S = 1

O = 4

H = 2

Number of atoms on product side are as follows.

S = 1

O = 4

H = 2

Therefore, this equation is balanced as it has same number of atoms on both reactant and product side.

(c)  

Number of atoms on  reactant side are as follows.

Sr = 1

O = 1

H = 2

S = 1

O = 4

Number of atoms on product side are as follows.

Sr = 1

O = 1

H = 2

S = 1

O = 4

Therefore, this equation is balanced.

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .

where are the choice options?