Chemistry, 02.09.2019 20:30 avaleasim

Determine the oxidation states of the elements in the following compounds
(a) nai
(b)gdcl3
(c)lino3
(d)h2se
(e)mg2si
(f)rbo2, rubidium superoxide
(g)hf

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Answer from: carcon2019

Explanation:

There are certain rules for determination of oxidation states of elements:

Oxidation states of elements in their elemental state is zero.The elements of the group 1 and group 2 of the periodic table (metals) have oxidation state of +1 and +2 respectively.Hydrogen has generally an oxidation number of +1 except when hydrogen is bonded to metals (say Na, K, etc) where it has an oxidation state of -1.Oxygen has an oxidation state of -2 generally. but in peroxides, its oxidation state is -1.Florine has an oxidation of -1 always as it is the most electronegative atom.Oxidation state of halogens is generally -1 if not bonded to more electronegative atom.

a) NaI

Na is a group 1 element, therefore its oxidation state is +1

Let the oxidation no. of I be x.

+1 + x = 0

x = -1

Oxidation state of Na in NaI = +1

Oxidation state of I in NaI = -1

b) GdCl_3

Oxidation state of Cl is -1 as it is more electronegative than Gd.

Let the oxidation no. of Gs be x.

x + -1×3 = 0

x = +3

Oxidation state of Gd in GdCl_3 = +3

Oxidation state of Cl in GdCl_3 = -1

c) LiNO_3

Li is a group 1 element, therefore its oxidation state is +1.

It is an oxide, so oxidation state of O is -2.

Let the oxidation no. of N be x.

+1 + x + -2×3 = 0

x = +5

Oxidation state of Li in = +1

Oxidation state of O = -2

Oxidation state of N = +5

d) H_2Se

As Se is more electronegative than H, so oxidation state of H is +1.

Let the oxidation no. of Se be x.

+1×2 + x = 0

x = -2

Oxidation state of H in H_2Se = +1

Oxidation state of Se in H_2Se = -2

e) Mg_2Si

Mg is a group 2 elements, so its oxidation state is +2

Let the oxidation state of Si be x.

+2×2 + x= 0

x = -4

Oxidation state of Mg in Mg_2Si = +2

Oxidation state of Si in tex]Mg_2Si[/tex] = -4

f) RbO_2

In oxides, oxidation state of O = -2

Let the oxidation state of Rb be x

x -2×2 += 0

x = +4

Oxidation state of Rb in RbO_2 = +4

Oxidation state of O in RbO_2 = -2

g) HF

F is the most electronegative element, so its oxidation state is -1

Oxidation state of H = +1

Answer from: Quest

when [oh-] is 10-5 m, and [h3o+] is 10-9 m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

Answer from: Quest

The reaction will shift to the right

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Determine the oxidation states of the elements in the following compounds
(a) nai
(b)gdc...

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