Solve the following problems, giving the answers to the proper number of sig figs.
a. 18.458m + 2.53m =
b. 8.4400m + 13.3m =
c. 8.46 x 10^2 x 2.62 x 10^5 =
d. 127.6g / 5.50ml =
e. 277 x 5.38 / 12.3=
f. 347.6m + 1.87 =
g. 0.02770 x 15.700 =
h. 3.07 x 10^-2 x 8.44 x 10^-6=
i. 0.1372 / 81.4 =
j. (7.31x10^4) + (3.23x10^3) =
k. 4.36dm x 2.34dm x 7.35dm=
l. (8.54x10^-3) - (3.41x10^-4)=

During trial 2, what allowed you to determine that aluminum was the limiting reactant? check all that apply. all of the copper dissolved. all of the aluminum dissolved. the solution turned clear. the number of grams of copper(ii) chloride used in the reaction was greater than the number of grams of aluminum. the molar ratio of copper(ii) chloride to aluminum was greater than 3: 2, the equation’s molar ratio.

What is a number added in front of a formula in order to balance the equation

Wind and moving water provide energy. chemical mechanical thermal none of the above