Given the balanced ionic equation: 2al(s) + 3cu2+(aq) → 2al3+(aq) + 3cu(s) compared to the total charge of the reactants, the total charge of the products is 1. less 2. greater 3. the same

3.- The same

Explanation:

1.- In the reactants you need to calculate the charges that you have:

2 Al(s) = zero, because the aluminum is in it based formed (that mean without charge).

3 Cu2+ = 3 x 2+ = 6+ That is the total positive charges that copper collaborate in this reaction.

2.- Then calculate the charges on the products:

2 Al3+ = 2 x 3+ = 6+ charges from the aluminum.

3 Cu(s) = zero, because the copper in this case is in the base form

3.- In this way, the charges at the begging (6+) and at the end (6+) are the same.

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.