Sc ample of argon a - 6 12 and 780 on what is the volume of this argas 5.79 what is the the temperature s a of o: os occupying 200 l at 100 ste? gas dalton's law of partial pressures-5.83, 5.05, 5.67 5.83 state dalton's law in words. 0.05 a gas mixture has three components n f and he. their partial pressures are 0.40 atm, 0.16 atm, and 0.78 atm, respectively. what is the pressure of the gas mixture? 5.87 a gas mixture has a total pressure of 0.56 atm and consists of he and ne. if the partial pressure of the he in the mixture is 0.27 atm, what is the partial pressure of the ne in the mixture?

1= c 2= a or d3 = idk sorry 4= c5= c

Ibelieve the answer is d

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.