break down the following question in a step by step easy to comprehend process.
when one atom of iodine-131 decays by beta particle emission, 1.5541 x 10^ -33 j are released. the atomic mass of the product nuclide is 130.9051 atomic mass units. write a nuclear reaction for the decay of iodine-131 and determine its atomic mass in amu. 1 amu = 1.66053886 x 10^ -27kg; mass of a b particle = 9.10938291 x 10^ -31kg

The atomic mass of  iodine-131 is 130.9056485 amu.

Explanation:

Beta-decay is the process in which a neutron gets converted into a proton and an electron releasing a beta-particle. The beta particle released carries a charge of -1 units.

Energy released during beta particle emission = E

Mass of reactant = Mass of product + Δm

=  Mass of beta particle + nuclide + Δm

Mass Beta-particle =

Mass of reactant =

=130.9051+0.000548579 amu + amu

= 130.9056485 amu

The atomic mass of  iodine-131 is 130.9056485 amu.

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.