Calculate the percent ionization of nitrous acid in a solution that is 0.222 m in nitrous acid (hno3) and 0.278 m in potassium nitrite (kno2). the acid dissociation constant of nitrous acid is 4.50 x 10-4 a) 55.6 b) 0.162 c) 15.5 d) 2.78 * 10-3

Explanation:

Concentration of is 0.278 M and it is completely ionized into and .

This means that = = 0.278 M

It is given that concentration of is 0.222 M.

As is a weak acid. Therefore, its dissociation will be as follows.

Initially :    0.222 M            0        0.278 M

Change :    - x                    +x           +x

Equilibrium : 0.222 M - x    x         0.278 M + x

Therefore, dissociation constant for this reaction will be as follows.

Hence, putting the given values into the above formula as follows.

                          x = 0.00036

As, is 0.00036 M. Therefore, percentage ionization of will be calculated as follows.

              % ionization of =

                               =

                               = 0.16 %

Thus, we can conclude that % ionization of is 0.16%.

no

explanation:

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