Aqueous solutions of sodium hypoch lorite (naoci), best known as bleach, are prepared by the reaction of sodium hydroxide with chlorine: 2 naoh (aq)cl2(g)-> naoci (aq)+ h20 (i)+ nacl (aq) how many grams of naoh are needed to react with 25.0 g of chlorine?

28.2 g of NaOH

Explanation:

We need to calculate the grams of NaOH needed to react with 25.0 g of Cl₂ in the following reaction:

2 NaOH(aq) + Cl₂(g) → NaOCI(aq + H₂0(I) + NaCl(aq)

We are going to solve this by making use of the molar ratio between Cl₂ and NaOH given by the reaction equation where we see that every mol of Cl₂ will react with 2 moles of NaOH.

So first we need to convert the 25.0 g of Cl₂ to moles:

Then we need to calculate the moles of NaOH needed to react with these moles of Cl₂ knowing that every mol of Cl₂ will react with 2 moles of NaOH:

Next we must convert these moles to grams:

28.2 g are needed to react with 25.0 g of Cl₂ in the production of NaOCl

b.final

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >