What is the mass, in grams, of 1.50 mol of iron (iii) sulfate? express your answer using three significant figures.

Answer : The mass of 1.50 mole of iron(III) sulfate is,

Explanation : Given,

Moles of iron(III) sulfate = 1.50 mole

Molar mass of iron(III) sulfate = 399.88 g/mole

The formula of iron(III) sulfate is,

Formula used :

Now put all the given values in this formula, we get:

Therefore, the mass of 1.50 mole of iron(III) sulfate is,

b

explanation:

mitosis