The density of liquid mercury is 13.5 g/cm^3. what mass of mercury (in kg) is required to fill a hollow cylinder having an inner diameter of 2.00 cm to a height of 25.0 cm? *

1.06 kg

Explanation:

Density is defined as the mass contained per unit volume.

Given :

Density of mercury =

volume of cylinder  = volume of mercury =

where r = radius of cylinder =

h= height = 25.0 cm

Putting in the values we get:

volume of mercury =

     (1kg=1000g)

Thus mass of mercury required to fill a hollow cylinder having an inner diameter of 2.00 cm to a height of 25.0 cm is 1.06 kg.

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm