In the laboratory a student combines 28.7 ml of a 0.240 m barium chloride solution with 17.5 ml of a 0.331 m chromium(ii) chloride solution. what is the final concentration of chloride anion ?

Answer : The final concentration of chloride ion is, 0.549 M

Explanation :

Barium chloride will furnish chloride ions as:

Given :

For barium chloride :

Molarity = 0.240 M

Volume = 28.7 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 28.7×10⁻³ L

Thus, moles of chlorine furnished by barium chloride is twice the moles of barium chloride as shown below:

Moles of chloride ions by barium chloride = 0.013776 moles

Chromium(II) chloride will furnish chloride ions as:

Given :

For chromium(II) chloride :

Molarity = 0.331 M

Volume = 17.5 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 17.5×10⁻³ L

Thus, moles of chlorine furnished by chromium(II) chloride is twice the moles of chromium(II) chloride as shown below:

Moles of chloride ions by chromium(II) chloride = 0.011585 moles

Total moles = 0.013776 moles + 0.011585 moles = 0.025361 moles

Total volume = (28.7×10⁻³ L) + (17.5×10⁻³ L) = 46.2×10⁻³ L

Concentration of chloride ions is:

Therefore, the final concentration of chloride anion is 0.549 M

o conteúdo de calor de um sistema é igual à entalpia apenas para um sistema que é constante

the answer is b because, investigating whether another species of moth also drinks tears might be interesting, but it would not directly explain why this species of moth does.

to explain why this species of moth drinks tears, the scientist could ask: "what nutrients that moths need are in elephant tears? "

the scientist could experiment with moth repellent or oter ways to keep the moths away, but that would not answer his original question.