Calculate the density of mercury if 1.00x10^2g occupies a bolume of 7.36 cm

Taking into account the definition of density, the density of mercury is 13.59 .

First you have to know that density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.  This is, density is the relationship that exists between the mass of a substance (or a body) and its volume.

It is an intrinsic property of matter because it does not depend on the amount of substance that is considered.

The expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

In this case, you know that:

Replacing in the definition of density:

Solving:

density= 13.59

Finally, the density of mercury is 13.59 .

Learn more about density:

13.6g/cm³

Explanation:

To calculate density of mercury we divide the mass by the volume.

1.00 × 10²g ÷ 7.36cm³ = 13.6g/cm³

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.