Amethod used by the u. s. environmental protection agency (epa) for determining the concentration of ozone in air is to pass the sample through a "bubbler" containing sodium iodide, which removes the ozone according to the chemical equation: o3(g) + 2 nai(aq) + h2o(l) → o2(g) + i2(s) + 2 naoh(aq) how many moles of sodium iodide are needed to remove 4.54 ✕ 10−6 mol of o3? mol nai how many milligrams of sodium iodide are needed to remove 13.31 mg of o3?

1. moles

2. 90 mg

Explanation:

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus moles of ozone is removed by = moles of sodium iodide.

Thus moles of sodium iodide are needed to remove moles of

2.

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by = moles of sodium iodide.

Mass of sodium iodide=    (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of .

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