Chemistry, 27.08.2019 01:20 taniaorozco

The mass of a glass beaker is known to be 24.8 g. approximately 5 ml of water are added, and the mass of the beaker and water is measured on an analytical balance to
be 30.625 g how many significant figures are there in the mass of the water?

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Answer from: cheylee123456

Two signficant figures.

Explanation:

You need to tell how many significant figures there are in the mass of water, which is calculated as the difference of two measures: 30.625 - 24.8.

You must round the mass of water to the least number of places in the decimal portion found in the two numbers that participate in the subtraction.

The least number of places in the decimal part corresponds to the measure 24.8 g and it is 1 decimal.

So, your answer must be rounded to 1 decimal:

Subtraction: 30.625 g - 24.8 g = 5.825 gRound to 1 decimal: 5.8 g

Some rules that you must follow to determine how many significant figures there are in a measure are:

Every non-zero digits in number are always significant. Also every zero between two significant digits are significant. Zeros in between the decimal point and the first a non-zero decimal digit are not significant. In a whole number final zeros cannot be taken as significant (e.g. it is ambiguos the number of significant digits in measures as 3,300).Trailing zeros to the right of a decimal point are significant.

So, in the 5.8 you apply the first rule: non-zero digits are always significant. So, the two digits in 5.8 are significant.

Answer from: Quest

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in $h_{2}s$ , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between $h_{2}s$ molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent $h_{2}s$ molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

Answer from: Quest

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