An unknown compound contains only the three elements c, h, and o. a pure sample of the compound is analyzed and found to be 65.60 percent c and 9.44 percent h by mass. (a) determine the empirical formula of the compound.

The empirical formula is

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C= 65.60 g

Mas of H = 9.44

Mass of O = (100-(65.6+9.44)= 24.96 g

Step 1 : convert given masses into moles.

Mass of C =

Moles of H =

Moles of O=

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =

For H =

For O =

The ratio of C:H:O= 3.5: 6: 1

Converting them into whole numbers, the ratio will be 7: 12: 2

Hence the empirical formula is

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

subscribe to my yt channel yoongi jmz

follow my insta yoongi_jams

stan bts