What is the energy released in the fission reaction 1 0 n + 235 92 u → 131 53 i + 89 39 y + 16 1 0 n 0 1 n + 92 235 u → 53 131 i + 39 89 y + 16 0 1 n ? (the atomic mass of 131 i 131 i is 130.9061246 u and that of 89 y 89 y is 88.9058483 u)

The energy released in the given nuclear reaction is 94.99 MeV.

Explanation:

For the given nuclear reaction:

We are given:

Mass of = 235.043924 u

Mass of = 1.008665 u

Mass of = 130.9061246 u

Mass of = 88.9058483 u u

To calculate the mass defect, we use the equation:

Putting values in above equation, we get:

To calculate the energy released, we use the equation:

 (Conversion factor:    )

Hence, the energy released in the given nuclear reaction is 94.99 MeV.

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."