Amixture containing kclo3,k2co3,khco3, and kcl was heated, producing co2,o2, and h2o gases according to the following equations: 2kclo3(s)? 2kcl(s)+3o2(g)2khco3(s)? k2o(s)+h2o(g)+2co2(g)k2co3(s)? k2o(s)+co2(g)the kcl does not react under the conditions of the reaction. 100.0 g of the mixture produces 1.90 g of h2o, 13.64 of co2, and 4.10 g of o2. (assume complete decomposition of the mixture.)1. how many grams of kclo3 were in the original mixture? 2.how many grams of khco3 were in the original mixture?

For 1: The mass of in the original mixture is 10.46 g

For 2: The mass of in the original mixture is 21.11 g

Explanation:

We are given:

Mass of water = 1.90 g

Mass of carbon dioxide = 13.64 g

Mass of oxygen = 4.10 g

The given chemical reaction for decomposition of follows:

By Stoichiometry of the reaction:

of oxygen is produced when of potassium chlorate is decomposed.

So, 4.10 g of oxygen will be produced when = of potassium chlorate is decomposed.

Amount of in the mixture = 10.46 g

The given chemical reaction for decomposition of follows:

By Stoichiometry of the reaction:

18 g of water is produced when of potassium bicarbonate is decomposed.

So, 1.90 g of water will be produced when = of potassium bicarbonate is decomposed.

Amount of in the mixture = 21.11 g

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< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >