2so2 (g) + o2 (g) 2 so3 (g)if the temperature on the equilibrium system is suddenly increased : the value of kc a. increasesb. decreasesc. remains the samethe value of qc a. is greater than kcb. is equal to kcc. is less than kcthe reaction must: a. run in the forward direction to restablish equilibrium. b. run in the reverse direction to restablish equilibrium. c. remain the same. already at equilibrium. the concentration of o2 will: a. increase. b. decrease. c. remain the same.

Part one: B. Kc decreases

Part two: B. Is equal to Kc

Part three: B. Run in the reverse direction to reestablish equilibrium

Part four: A. Increase

Explanation:

Part one: Sulfur dioxide combines with oxygen to form sulphur trioxide in an exothermic reaction. If the temperature is suddenly is increased, while the reaction is at equilibrium, the backward reaction (the endothermic one) is favored to "sweep up the excess heat". An increase in reactants means a decrease in Kc since the denominator(reactants) is becoming bigger while the numerator (products) become smaller.

Part two: Qc is a varying version of Kc. For this set of circumstances, it will be equal to Kc since Kc varies with temperature

Part three: The reaction must run in the reverse to reestablish the equilibrium.

Part four: The concentration of of oxygen will increase as more of the reactants are formed

i think the answer is terrae but not 100 percent sure. ▓▬▬ §