1) which method would be the best for separating the salts from seawater?
a. gas chromatography
b. filtration with a paper filter
c. distillation
d. freezing
2) which example is a mixture
a. alcohol
b. water
c. mercury
d. orange soda
3) which example is a homogenous mixture?
a. seawater
b. chunky salsa
c. vegetable soup
d. fruit salad

Explanation:

1. c. distillation

The best method to separate salt from sea water is by distillation.

What is distallation and why the choice?

Distillation is a separation technique that can be used to recover solvents from their solutions.

Most importantly, it involves seperation of components that have an appreciable difference in their boiling points.

To recover salts which is a solute dissolved in the water(sea water) , the solution is boiled to vaporize the solvent. When water reaches its boiling point, vaporization begins to occur. As the liquid water turns to vapor, the solute which is the salt remains in the distillation flask and can easily be dried and collected.

2. d. orange soda

A mixture is a substance which has the following properties:

a. Composition is indefinite

b. Constituents retain their identities

c. They can easily be separated by physical methods.

From the options given, orange soda perfectly fits the description.

Alcohol is an organic compound

Water is a compound

Mercury is an element with Hg as its symbol.

3. a. seawater

A homogenous mixture is one in which its constituents exists in just one phase. Sea water is one of such mixtures. Here, water dissolves the salts as they are brought into it. This leaves both the water and salt in the liquid uniform phase.

The rest of the options provided are heterogeneous mixtures in which the constituents are in different phases. Vegetable soup for example has a solid and liquid phase.

answer is: empirical formula is tl₂o. if we use 100 grams of compound, tha:

m(tl) = 96.2%  · 100 g ÷ 100%.

m(tl) = 96.2 g.

n(tl) = m(tl)  ÷ m(tl). n(tl) = 96.2 g  ÷ 204.4 g/mol.

n(tl) = 0.47 mol. m(o) = 3.77 g. n(o) = m(o)  ÷ m(o). n(o) = 3.77 g  ÷ 16 g/mol. n(ag) = 0.235 mol. n(tl) . n(o) = 0.47 mol : 0.235 mol /0.235. n(tl) . n(o) = 2 : 1.

m(tl₂o) = 204.4 g/mol  · 2 + 16 g/mol = 424.8 g/mol.

m(compound) = 456. 8 g/mol - 424.8 g/mol = 32 g/mol ( 2 oxygens); tl₂o₃.