In order to reduce dependence on imported oil, the government of jalica has imposed minimum fuel-efficiency requirements on all new cars, beginning this year. the more fuel-efficient a car, the less pollution it produces per mile driven. as jalicans replace their old cars with cars that meet the new requirements, annual pollution from car traffic is likely to decrease in jalica. which of the following, if true, most seriously weakens the argument‘? (a) in jalica, domestically produced oil is more expensive than imported oil.(b) the jalican government did not intend the new fuel-efiiciency requirement to be a pollution-reduction measure.(c) some pollution-control devices mandated in jalica make cars less fuel-efficient than they would be without those devices.(d) the new regulation requires no change in the chemical formulation of fuel for cars in jalica.(e) jalicans who get cars that are more fuel-efficient tend to do more driving than before.

(B) The Jalican government did not intend the new fuel-efiiciency requirement to be a pollution-reduction measure.

Explanation:

What it was expressed is about to reduce dependence on imported oil.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.