Chlorine is used to disinfect swimming pools. the accepted concentration for this purpose is 1 ppm chlorine, or 1 g of chlorine per million grams of water. calculate the volume of a chlorine solution (in milliliters) a homeowner should add to her swimming pool if the solution contains 6.0 percent chlorine by mass and there are 2.0 x 10^4 gallons (gal) of water in the pool (1 gal =3.79 l; density of liquids= 1.0 g/ml).

Volume of chlorine solution required is around 1.2 L

Explanation:

Volume of water in the pool = 2.0*10^4 gal

1 gal = 3.79 L

Therefore, volume of water in the pool in units of Liters would be:

Density of water = 1 g/ml = 1000 g/L

The accepted concentration of chlorine = 1 g/ 10⁶ g water

Therefore amount of chlorine required to disinfect the pool water would be:

The given solution is 6.0% w/w chlorine i.e.

6.0 g chlorine in 100 g solution

Therefore, amount of solution corresponding to 74 g chlorine would be:

Density of the solution = 1 g/ml

fe 55.85 g/mol and h2o 18.02 g/mol.