Complete the following conversions between si units.
(a) 612 g =
(b) 8.160 m=
(c) 3779 âµg=
(d) 781 ml =
(e) 4.18 kg =
(f) 27.8 m =
(g) 0.13 ml=
(h) 1738 km =
(i) 1.9 gg=

For a:  

For b:  8.160 m = 816.0 cm

For c:  

For d:  781 mL = 0.781 L

For e:  4.18 kg = 4180 g

For f:  27.8 m = 0.0278 km

For g:  

For h:  

For i:  

Explanation:

Units is defined as the standard which is used to make comparisons between the measurements.

For the given options:

The conversion factor used is:

So,

The conversion factor used is:

So,

The conversion factor used is:

So,

The conversion factor used is:

So,

The conversion factor used is:

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The conversion factor used is:

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The conversion factor used is:

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The conversion factor used is:

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The conversion factor used is:

So,

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol