Identify the oxidation number of the element indicated. 1.) carbon in coh. o 2.) phosphorus in hpo: 3.) manganese in mno(oh) 4.) nitrogen in n: os balance each equation by inspection. i. ii. mg(cio), ? mgcl2 + 3 o2 iii. identify the following data using the given equation. al(s) +mnomno(s) +al(oh) ) the substance reduced: 2.) the oxidation number of mn in mno. 3.) the oxidizing agent: 4.) the electron acceptor: 5.) the substance oxidized: 6.) the electron donor: 7.) the reducing agent: 8.) the oxidation number of al in al(oh)

58750.08068 is the answer i think

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)

what is the question here. i think you messed up.

it is stable as it is in group 0 which have full outer shells of electrons