What is the temperature of 13.3 moles of carbon dioxide that occupies 6 m3 and applies a pressure of 23 kpa to its container?

T = 1248 K

Explanation:

We can calculate the T, by using the ideal gas law:

PV = nRT

Where we have:  

The pressure P, volume V, and temperature T, R is the gas constant, and n is the number of moles of the gas.  

According to the international unit systems R is 8.314 J/(K·mol)

With this value the P unit will be Pa and the V unit will be m³.  

Then,  

T = PV / nR  

T = (23 × 1000 × 6) / (13.3 × 8.314)  

T = 1248 K