Which correctly lists the following in order of increasing entropy? i. 1 mol of hcl (g) at 50 ° c ii. 1 mol of nacl (s) at 25 ° c iii. 2 mol of hcl (g) at 50 ° c iv. 1 mol of hcl (g) at 25 ° c

The order of increasing entropy will be:

1 mol of NaCl (s) at 25 ° C < 1 mol of HCl (g) at 25 ° C<  1 mol of HCl (g) at 50 ° C < 2 mol of HCl (g) at 50 ° C

Explanation:

The entropy increases with

a) increase in temperature

b) state of matter (the entropy order of matter is gas > liquid > solid)

So here

i) 1 mol of HCl (g) at 50 ° C : it is gas at high temperature as compared to HCl gas at lower temperature.

ii. 1 mol of NaCl (s) at 25 ° C : this is solid so will have lower entropy than gas.

iii. 2 mol of HCl (g) at 50 ° C: the moles are more so will have more entropy than 1 mol of HCl (g) at 50 ° C

iv. 1 mol of HCl (g) at 25 ° C : will have lower entropy than HCl gas at higher temperature but will have higher entropy than solid NaCl.

- both b and d.

-since b and d are the closest coastlines then that makes it the most affected.

< 3

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :