At the equivalence point of a khp/naoh titration, you have added enough oh- to react with all of the hp- such that the only species left in solution are p2- (the conjugate base of hp-) and the spectator ions na+ and k+. if a titration of khp with naoh resulted in [p2-] = 0.042 m at the equivalence point, what is the ph of the solution? ka for hp- = 3.9 x 10^-6. a. 3.40 b. 4.98 c. 7.00 d. 9.02 e. 10.61

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i think it's c. if you look search electronic symbol on google and then click on wiki it shows you a