One kmol of ethane gas (ch4) is burned completely with 20% excess air during a steady flow 25°c the water in the products exits in the liquid form combustion process. the fuel and air enter the combustion chamber at 25*c, and the products leave at a) determine the mole number of the products and the reactants, and write the reaction. (15 b) write the energy balance equation (complete form with all the terms for each reactant and points) product) and determine the heat rejected in this process, in kü/kmol of fuel.

Well technically there are two correct answers b and d. but for you its probably b in general.good day sir/ma'am : ) (i know not gender)

The correct answer is:   bri hope this answer was ! : )

I️i️ is a really time of to get go back home alone to the sleep

Given data,temperature, t = 230°c = 503 kconsider the chemical reaction,ch₃oh(l) + 1/2 o₂(g)  → ch₂o(g) + h₂o(l)calculate the enthalpy change for the reaction: δh⁰rxn =  σnδh⁰f(products) -  σmδh⁰f(reactants)substitute the values from the table: δh⁰rxn = { -115.9 + (-285.8)} - {0+(-238.7)}              = -163.0 kjcalculate the entropy change for the reaction.δs⁰rxn = (219 + 70) - (127.2 + 1/2 x 205.2) = 59.2 j/kconsider the expression for free energy: δg⁰rxn =  δh⁰rxn - t  δs⁰rxnsubstitute the values in the above equationδg⁰rxn = -163 x 10³ - (503 x 59.2)              = -192777.6 j              = -192.777 kj