Consider the following reaction at equilibrium. what effect will removing no2 have on the system? so2(g) + no2(g) ↔ so3(g) + no(g) consider the following reaction at equilibrium. what effect will removing no2 have on the system? so2(g) + no2(g) so3(g) + no(g) the reaction will shift to decrease the pressure. the equilibrium constant will decrease. the reaction will shift in the direction of reactants. the reaction will shift in the direction of products. no change will occur since so3 is not included in the equilibrium expression.

Answer

The equilibrium of the reaction will shift to the left/reactant side

Explanation:

According to Le Chatelier's principle, a reversible reaction at equilibrium will react such that it does the opposite of what has been done to it until it reaches a new equilibrium. What has been done to the system here is there has been a removal of NO2 so the reaction will ADD it back by breaking down the products to form NO2. So the reaction will move backward/to the left/towards the reactant

answer: mole of the gas

answer: mole of the gasexplanation: