Arigid tank contains 20 lbm of air at 20 psia and 70°f. more air is added to the tank until the pressure and temperature rise to 23.5 psia and 90°f, respectively. determine the amount of air added to the tank. the gas constant of air is r

Answer : The amount of air added to the tank will be, 1.2062 Kg.

Explanation :

First we have to calculate the volume of air by using ideal gas equation.

where,

= initial pressure of air =

conversion used :

= initial temperature of air =

conversion used :

= initial volume of air = ?

= initial mass of air =

conversion used :

R = gas constant = 0.0821 L.atm/mole.K

M = molar mass of air

Now put all the given values in the above expression, we get:

Now we have to calculate the final amount of air by using ideal gas equation.

where,

= final pressure of air =

= final temperature of air =

= final volume of air =

= final mass of air = ?

R = gas constant = 0.0821 L.atm/mole.K

M = molar mass of air

Now put all the given values in the above expression, we get:

Now we have to calculate the amount of air added to the tank.

conversion used : (1 Kg = 1000 g)

Hence, the amount of air added to the tank will be, 1.2062 Kg.

- decrease the number of plants and animals living in the water.