During the winter months, many locations experience snow and ice storms. it is a common practice to treat roadways and sidewalks with salt, such as caco3 . if a 11.3 kg bag of caco3 is used to treat the sidewalk, how many moles of caco3 does this bag contain?

The number of moles of CaCO3 on the bag is 112.90 moles

Explanation:

number mole (n) = mass (m) divided by molecular mass (Mm)

Mm of CaCO3 = 100.0869 g/mole

mass in grams = 11.3 Kg x (10^3 g/1 Kg) = 11300 grams

number of moles (n) = 11300 grams divided by 100.0869 grams per mole = 112.90 moles of CaCO3 in the bag.

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

sry but any answer choices