Diatomic iodine [i2] decomposes at high temperature to form i atoms according to the reaction i2(g)⇌2i(g), kc = 0.011 at 1200∘c in an equilibrium mixture, the concentration of i2 is 0.10 m. what is the equilibrium concentration of i? express your answer using two significant figures.

The concentration of I at equilibrium = 3.3166×10⁻² M

Explanation:

For the equilibrium reaction,

I₂ (g) ⇄ 2I (g)

The expression for Kc for the reaction is:

Given:

= 0.10 M

Kc = 0.011

Applying in the above formula to find the equilibrium concentration of I as:

So,

Thus, The concentration of I at equilibrium = 3.3166×10⁻² M

b. acid is the correct answer @jayxboof all social media

acid : acids are those which accepts an electron-pairs.

base : bases are those which donates ab electron-pairs.

alkali : it is a base that dissolves in water. it is basically a base and the ph greater than 7.

hydroxide ion : it is a poly-atomic ion which is negatively charged.