Asurgeon needs 9 liters of a 3% saline solution. she has a 1% solution and a 10% solution available. how many liters of the 1% solution and how many liters of the 10% solution should she mix to make the 3% solution?

7 L of the 1% solution and 2 L of the 10% solution should she mix to make the 9 L of  3% solution.

Explanation:

Let the volume of 1% solution be mixed to make 3% solution= a L

Let the volume of 10% solution be mixed to make 3% solution= b L

Given , Volume of  3% solution = 9 L

Thus, a + b = 9 1

Also,

Applying C₁V₁ + C₂V₂ = C₃V₃

Where,

C₁ is the concentration of the 1% liquid

C₂ is the concentration of the 10% liquid

C₃ is the concentration of the 3% liquid

V₁ is the volume of the 1% liquid (a L)

V₂ is the volume of the 10% liquid (b L)

V₃  is the volume of the 3% liquid (9 L)

So,

1×a + 10×b = 9×3

a + 10b = 27  2

Solving equation 1 and 2 , we get:

a = 7 L and b = 2 L

Thus, 7 L of the 1% solution and 2 L of the 10% solution should she mix to make the 3% solution.

i think its 100.

hope this !