Which of the following is correctly ranked in order of increasing bond polarity? o-o < o-f cl-s < cl-br al-o < p-o h-h < n-n b-f < c-f f-o < o-o li-f < c-o

O-O<O-F

option 1 is correct.

Explanation: The bond polarity can be explained on the basis electronegative difference between the atoms.

Greater the electronegativity difference between the two atoms in a bond greater is the polarity of the bond.

Electronegativity difference of a bond between two atoms =EN of atom having higher electronegativity- EN of atom having lower electronegativity

Likewise we can calculate the electronegativity difference for the following bonds and estimate there bond polarities.

1.EN[O-O]=EN(O)-EN(O)=(3.44)-(3.44)=0

EN[O-F]=EN(F)-EN(O)=(3.98)-(3.44)=0.54

So the bond polarity of O-F is more than O-O as it has more electronegativity difference. These two species are correctly arranged as O-O<O-F

2.EN[Cl-S]=EN(S)-EN(Cl)=(3.16)-(2.58)=0.58

EN[Cl-Br]=EN(Cl)-EN(Br)=(3.16)-(2.96)=0.20

So the bond polarity of Cl-S is more than Cl-Br as it has more electronegativity difference. These two species are incorrectly arranged as Cl-S>Cl-Br.

3. EN[Al-O]=EN(O)-EN(Al)=(3.44)-(1.61)=1.83

EN[P-O]=EN(O)-EN(P)=(3.44)-(2.19)=1.25

So the bond polarity of Al-O is more than P-O as it has more electronegativity difference. These two species are incorrectly arranged as Al-O>P-O.

4.EN[H-H]=EN(H)-EN(H)=(2.2)-(2.2)=0

EN[N-N]=EN(H)-EN(N)=(3.04)-(3.04)=0

The electronegativity difference for both the bonds is 0 hence both the bonds would not have any polarity. Hence the mentioned order is incorrect.  

5. EN[B--]=EN(F)-EN(B)=(3.98)-(2.04)=1.94

EN[C-F]=EN(F)-EN(C)=(3.98)-(2.55)=1.43

So the bond polarity of B-- is more than C-F as it has more electronegativity difference. These two species are incorrectly arranged as B-->C-F

6. EN[Li-F]=EN(F)-EN(Li)=(3.98)-(0.98)=3.0

EN[C-O]=EN(O)-EN(C)=(3.44)-(2.55)=0.89.

So the bond polarity of Li-F is more than C-O as it has more electronegativity difference. These two species are incorrectly arranged as Li-F>C-O

7. EN[F-O]=EN(F)-EN(O)=(3.98)-(3.44)=0.54

EN[O-O]=EN(O)-EN(O)=(3.44)-(3.44)=0

So the bond polarity of F-O is more than O-O as it has more

electronegativity difference. So it is incorrectly arranged.

the answer is a and have a great day