A50% antifreeze solution is to be mixed with a 90% antifreeze solution to get 200 liters of a 80% solution. how many liters of the 50% solution and how many liters of the 90% solution will be used?

50 ltr 150 ltr

Explanation:

this problem can be solved by the mixture and allegation concept which can be clearly understand from bellow figure in which the concentration of solution 1 is 50% and concentration of solution 2 is 90% before mixing after mixing with help bellow concept the ratio of concentration become 10:30

ratio of solution 1 and solution 2 =10:30

                                                     =1:3

total mixture is 200 liters

part of solution 1= ×200

                           =50 liters

part of solution 2= ×200

                           =150 liters

where are the choice options?

it is the most commonly accepted one