The density of an aqueousâ solution of sulfuric acid is 1.36 g/ml and the concentration is 3.43 m.â what is the concentration of this solution in percent by mass?

2.40%

Explanation:

Density of a substance is given as the mass divided by the volume ,

Hence from the question ,

density of sulfuric acid = 1.35 g/mL

i.e.

1mL of sulfuric acid solution = 1.35 g of sulfuric acid ,

Hence,

1000mL of sulfuric acid solution = 1.35 * 1000 g of sulfuric acid,

i.e.

1000mL of sulfuric acid solution = 13500 g of sulfuric acid,

Now, Molarity of a solution is given by the moles of solute per liter of the solution .

Hence,

M = moles of solute / volume of solution (in L)

From question , '

3.43 M of sulfuric acid ,

Hence,

In 1 L of solution , 3.34 moles of sulfuric acid are present,

Now,

Moles are calculated as the given mass divided by the molecular mass.

The molecular mass of sulfuric acid is 98 g /mol

moles = ( mass / molecular mass )

therefore,

mass = moles * molecular mass

i.e.

mass of sulfuric acid = 3.34 mol * 98 g/mol = 327.32 g

Now, to calculate the mass percentage of sulfuric acid , is given by the mass of sulfuric acid divided by the mass of the total solution multiplied by 100.

therefore,

mass of sulfuric acid = 327.32 / 13600 * 100

Hence, mass of sulfuric acid = 2.40%

b. acid is the correct answer @jayxboof all social media

acid : acids are those which accepts an electron-pairs.

base : bases are those which donates ab electron-pairs.

alkali : it is a base that dissolves in water. it is basically a base and the ph greater than 7.

hydroxide ion : it is a poly-atomic ion which is negatively charged.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml