How many joules are absorbed when 64.3 grams of water is heated from 40.0 °c to 74.0 °c?
a. 7,330 joules
b. 9,150 joules
c. 10,100 joules
d. 12,800 joules

Answer : The correct option is, (B) 9150 joules

Explanation : Given,

Initial temperature =

Final temperature =

Mass of water = 64.3 g

Specific heat of water =

Formula used :

or,

where,

Q = heat absorbed = ?

m = mass of water

= specific heat of water

= initial temperature

= final temperature

Now put all the given value in the above formula, we get:

Therefore, the heat absorbed will be, 9150 J

is has three carbons, so the answer is propylamine.

meth-

eth-

prop-

but-

pent-

hex-

hept-

oct-

non-

explanation:

i would say b

explanation:

but i think i would need more information than that