70 points and will give brainliest
baking soda (nahco3) can be added to a fruit mix solution to create a carbonated drink. an example is a reaction between baking soda and citric acid below.
c6h8o7 + 3nahco3 → na3c6h5o7 + 3h2o + 3co2
citric acid – 192.0 g/mol baking soda – 84.0 g/mol
how many milliliters of a 0.8 m solution of citric acid would be needed to react with 15 grams of baking soda? show your work.

74mL

Explanation:

Given parameters:

Molar mass of citric acid = 192g/mol

Molar mass of baking soda = 84g/mol

Concentration of citric acid  = 0.8M

Mass of baking powder = 15g

Unknown parameters:

Volume of citric acid = ?

Solution

       Equation of the reaction:

            C₆H₈O₇ + 3NaHCO₃ → Na₃C₆H₅O₇ + 3H₂O + 3CO₂

Procedure:

We work from the known parameters to the unknown. From the statement of the problem, we can approach the solution from the parameters of the baking powder. From the baking powder, we can establish a molar relationship between the two reactants. We employ the mole concept in this regard. We find the number of moles of the baking powder that went into the reaction using the expression below:

                Number of moles =

                Number of moles =   = 0.179mole

From the equation of the reaction, we can find the number of moles of the citric acid:

             3 moles of baking powder reacted with 1 mole of citric acid

 0.179 moles of baking powder would react with :

          This yields 0.059mole of citric acid

To find the volume of the citric acid, we use the mole expression below:

    Volume of citric acid =

Volume of citric acid = = 0.074L

Expressing in mL gives 74mL

               

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Mass of water is smething that you froma drug test or sum girl ya