What is the entropy change of the system when 17.5 g of liquid benzene (c6h6) evaporates at the normal boiling point? the normal boiling point of benzene is 80.1°c and δh vap is 30.7 kj/mol.

Answer : The entropy change of the system is, 19.5 J/K

Solution :

First we have to calculate the moles of benzene.

Now we have to calculate the entropy change of the system.

Formula used :

where,

= entropy change of the system = ?

= enthalpy of vaporization = 30.7 kJ/mole

n = number of moles of benzene  = 0.224 mole

= normal boiling point of benzene =

Now put all the given values in the above formula, we get the entropy change of the system.

Therefore, the entropy change of the system is, 19.5 J/K

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