An sample of water with a mass of 123.00 kg is heated from 25 c to 97 c. if the specific heat of water is 1 j-1 kg k-1 then how much energy is required?

The amount of energy required will be 8856 Joules.

Explanation:

To calculate the amount of heat absorbed, we use the equation:

where,

Q = heat absorbed or released

m = Mass of the substance = 123 kg

c = specific heat capacity of water =

= change in temperature =  (change remains the same)

Putting values in above equation, we get:

Hence, the amount of energy required will be 8856 Joules.

answer; /// the amount of material dissolved in a measure of liquid(concentration) the above statement is (true); /// good luck