How many liters of 3.0 m naoh solution will react with 0.60 liters of 4.0 m h2so4?
h2so4 + naoh → na2so4 + h2o
1.2 l
1.6 l
2.4 l
2.8 l

Volume of NaOH reacted = 1.6 L

Explanation:

Given:

Molarity of H2SO4, M1 = 4.0 M

Volume of H2SO4, V1 = 0.6 L

Molarity of NaOH, M2 = 3.0 M

To determine:

Volume of NaOH,V2

Explanation:

The given neutralization reaction is:

Here 2 moles of NaOH reacts with 1 mole of H2SO4

i.e. moles of NaOH = 2(moles of H2SO4)

Since:

The volume of NaOH solution is 1.6 L

Explanation:

To calculate the volume of base, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is

are the n-factor, molarity and volume of base which is NaOH.

We are given:

Putting values in above equation, we get:

Hence, the volume of NaOH solution is 1.6 L