Consider the hypothetical reaction a((g). a flask is charged with 0.73atm of pure a, after which it is allowed to reach equilibrium at 0 ? c. at equilibrium the partial pressure of a is 0.37atm .
a: what is the total pressure in the flask at equilibrium?
b: what is the value of kp?

1.08 atm is the total pressure in the flask at equilibrium.

The value of the .

Explanation:

Partial pressure of A at equilibrium =

Partial pressure of B at equilibrium =

                           A(g)      ⇄    2B(g)

at t=0                 0.73 atm           0

At equilibrium  (0.73- x)         2x

x = 0.36 atm

Total pressure in the flask at equilibrium = P

The expression of equilibrium constant will be given as:

yes they ca   is ur ansswerrr

the correct option is c.

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