Two systems with heat capacities 19.9 j mol-1 k-1 and 28.2 ] mol 1 k-1 respectively interact thermally and come to an equilibrium temperature of 300c. if the initial temperature of system 1 was 450c, what was the initial temperature of system 2 in °c? you may assume that the total energy of the combined systems remains constant

Answer : The initial temperature of system 2 is,

Explanation :

In this problem we assumed that the total energy of the combined systems remains constant.

The mass remains same.

where,

= heat capacity of system 1 = 19.9 J/mole.K

= heat capacity of system 2 = 28.2 J/mole.K

= final temperature of system =

= initial temperature of system 1 =

= initial temperature of system 2 = ?

Now put all the given values in the above formula, we get

Therefore, the initial temperature of system 2 is,

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole