How many moles of sodium chloride are present in 0.50 kg of a 1.0 m solution of sodium chloride in water? mol sodium chloride

=0.5 moles

Explanation:

Let us assume that the sodium chloride solution has a density of 1g/cm³.

Therefore the volume of the 0.5 kg of solution will be calculated as follows.

0.5kg into grams=0.5 kg×1000g/kg

=500g

volume= mass/density

=500g/1g/cm³

=500cm³

The solution is 1.0 M which means that 1.0 moles are in 1000 cm³

500cm³ will have:

(500 cm³×1.0 moles)/1000 cm³

=0.5 moles

the answer is   c.) 1575 j.

explanation:

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :