Chemistry, 05.02.2020 12:53 leo4687

The chemical formula for ferric sulfate is fe(so4)3. determine the following:

a) the number of sulfur atoms in 1.75 mole of fe(so4)3
b) the mass in grams of 2.65 mol of fe(so4)3
c) the number of moles of fe(so4)3 in 3.45 grams of fe(so4)3.
d)the mass in grams of 3 formula unit of fe(so4)3

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Answer from: AM28

Answer :

(a) The number of sulfur atoms are, $31.61\times 10^{23}$ .

(b) The mass of the mass of Fe_2(SO_4)_3 is, 1059.682 grams.

(d) The mass of the mass of Fe_2(SO_4)_3 is, $19.95\times 10^{-22}g$

Explanation :

(a) As we are given the number of moles of Fe_2(SO_4)_3 is, 1.75 mole. Now we have to calculate the number of sulfur atoms.

In the Fe_2(SO_4)_3 , there are 2 iron atoms, 3 sulfur atoms, 12 oxygen atoms.

As, 1 mole of Fe_2(SO_4)_3 contains $3\times 6.022\times 10^{23}$ number of sulfur atoms.

So, 1.75 mole of Fe_2(SO_4)_3 contains $1.75\times 3\times 6.022\times 10^{23}=31.61\times 10^{23}$ number of sulfur atoms.

The number of sulfur atoms are, $31.61\times 10^{23}$

(b) As we are given the number of moles of Fe_2(SO_4)_3 is, 2.65 mole. Now we have to calculate the mass of .

$\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times \text{Molar mass of }Fe_2(SO_4)_3$

The molar mass of Fe_2(SO_4)_3 = 399.88 g/mole

$\text{Mass of }Fe_2(SO_4)_3=2.65mole\times 399.88g/mole=1059.682g$

The mass of the mass of Fe_2(SO_4)_3 is, 1059.682 grams.

$\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times \text{Molar mass of }Fe_2(SO_4)_3$

The molar mass of Fe_2(SO_4)_3 = 399.88 g/mole

$3.45g=\text{Moles of }Fe_2(SO_4)_3\times 399.88g/mole$

$\text{Moles of }Fe_2(SO_4)_3=8.63\times 10^{-3}mole$

The number of moles of Fe_2(SO_4)_3 is, $8.63\times 10^{-3}mole$

(d) As we are given the formula unit of Fe_2(SO_4)_3 is, 3. Now we have to calculate the mass of .

As we know that 1 mole of Fe_2(SO_4)_3 contains $6.022\times 10^{23}$ formula unit.

Formula used :

$\text{Formula unit of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times 6.022\times 10^{23}$

$3=\text{Moles of }Fe_2(SO_4)_3\times 6.022\times 10^{23}$

$\text{Moles of }Fe_2(SO_4)_3=4.989\times 10^{-24}mole$

Now we have to calculate the mass of Fe_2(SO_4)_3 .

$\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3\times \text{Molar mass of }Fe_2(SO_4)_3$

The molar mass of Fe_2(SO_4)_3 = 399.88 g/mole

$\text{Mass of }Fe_2(SO_4)_3=4.989\times 10^{-24}mole\times 399.88g/mole=19.95\times 10^{-22}g$

The mass of the mass of Fe_2(SO_4)_3 is, $19.95\times 10^{-22}g$

Answer from: Quest

answer: mercury

explanation:

Which of these is not a commonly mined metallic substance?

Answer from: Quest

most historians agree that gabriel mouton, the vicar of st. paul’s church in lyons, france, is the “founding father” of the metric system. he proposed a decimal system of measurement in 1670. mouton based it on the length of one minute of arc of a great circle of the earth (now called a nautical mile, 1852 meters). he also proposed the swing-length of a pendulum with a frequency of one beat per second as the unit of length (about 25 cm). a pendulum beating with this length would have been fairly easy to produce, thus facilitating the widespread distribution of uniform standards. over the years, his work was revised, improved, and extended by a number of french scientists.

the political sponsor of weights and measures reform in the french revolutionary national assembly was the bishop of autun, better known as talleyrand. under his auspices, the french academy appointed several committees to carry out the work of developing a usable system of weights and measures for france. one of the committees recommended a decimalized measurement system based upon a length equal to one ten-millionth of the length of a quadrant of the earth’s meridian (i.e., one ten-millionth of the distance between the equator and the north pole).

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The chemical formula for ferric sulfate is fe(so4)3. determine the following:

a) the nu...

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