Which statement is true about an acidic solution?
a. its ph is equal to 7.
b. its ph is greater than 7.
c. it has a greater concentration of hydronium ion than hydroxide ions.
d. it has a greater concentration of hydroxide ion than hydronium ions.

C. It has a greater concentration of hydronium ion than hydroxide ions.

Explanation:

An acidic solution is one in which the concentration of hydronium ions is greater than that of hydroxide ions. This makes the pH less than 7. An acidic solution is an electrolyte and conducts electricity.

                        [H₃O⁺] > [OH⁻] for an acidic solution

A basic solution has a greater concentration of hydroxide ions than hydrogen ions and it has a pH greater than 7.

it has a greater concentration of hydronium ion than hydroxide ions

Explanation:

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years

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explanation:

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